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#31 (permalink)      3/29/2015 3:49:07 PM US Central   quote/reply + tips
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Snorkelwhacker
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Twist it any way you like but heat can be measured in watts. Yes, the more mass in your coil, the more heat (watts, power) that's wasted simply bring it to temp.

Still, if you're after heat you're after watts. There's simply no escaping that.
Rube Goldberg would get a kick out of "temperature control" devices.
#32 (permalink)      3/29/2015 4:33:34 PM US Central   quote/reply + tips
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Migweld
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sh00kre wrote:

I also have https://www.fasttech.com/products/1840800 (0,38mm) and 0.30mm which i dont like (at least on RDA's)...Will purchase 28AWG for maybe better "sweet spot" or more possibly throw this little restricted bastard in the wall :D...


if you find your limited in room for your wire this will help
and will heat up fast, but 28g not needed if you play about with the inner diameter...

try to make inner diameter of the coil bigger with your 26g for a 0.6Ω coil
less room needed but bigger thicker wick, also try a none 'micro' type coil.
use COIL SPACING...

26g
5 wraps to get 0.65Ω
3mm inner diameter,
(3.5mm inner dia, 4 wraps, 0.6Ω)

if your going to use 28g best to make inner diameter smaller 2mm to 2.5mm
you can always make more room with a bigger inner diameter for less wraps
with the 26g wire you have...


Edited on 3/29/2015 at 5:00 PM. Reason:
#33 (permalink)      3/29/2015 5:55:27 PM US Central   quote/reply + tips
sh00kre
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Thanks Migweld, i tried (what RIP trippers calls) macro coil on i think 3mm diameter screwdriver, will try on bigger one!
And we are speaking about dual coils? Because with 26awg 2x 8 wraps i got 0.46 and with 2x 7 wraps 0.38(around 27awg) i got those 0.5ohms.
#34 (permalink)      3/29/2015 6:48:58 PM US Central   quote/reply + tips
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Migweld
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if using dual coils then 28g or 27g will work best..
fine tune with big inn dia.

this..

27g
Wraps: 2 x 7
3.5mm inn dia
0.30mm space between windings
Resistance 0.6 Ω
3.0V-15W, 4.2V-30W



this..

28g
Wraps: 2 x 6
3.5mm inner dia
0.30mm space between windings
Resistance 0.64 Ω
3.0V-14W, 4.2V-28W, 4.7V-35W
#35 (permalink)      3/29/2015 7:27:29 PM US Central   quote/reply + tips
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Nymzavril
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Lol, I want all my future regulated mods to have a read out in BTUs.
Grand Poobah of The Sacred Order of The Magick Blue Screwdriver. The old Juice Junkies FAQ and guides can be found here: https://www.dropbox.com/sh/vp4ktp8l7fdywg5/AABFkmnUJhjl9vX8tE4URZ8sa?dl=0
#36 (permalink)      3/29/2015 7:29:15 PM US Central   quote/reply + tips
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Nymzavril
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That or the scoville scale for chilli peppers. Hehehehe
Grand Poobah of The Sacred Order of The Magick Blue Screwdriver. The old Juice Junkies FAQ and guides can be found here: https://www.dropbox.com/sh/vp4ktp8l7fdywg5/AABFkmnUJhjl9vX8tE4URZ8sa?dl=0
#37 (permalink)      3/29/2015 9:11:03 PM US Central   quote/reply + tips
JPBel
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Snorkelwhacker wrote:

Twist it any way you like but heat can be measured in watts. Yes, the more mass in your coil, the more heat (watts, power) that's wasted simply bring it to temp.

Still, if you're after heat you're after watts. There's simply no escaping that.


who was talking about mass ?
Increasing the resistance does'nt necessarily = more mass, what do you think you are doing when you put coils in parallel ?.
You are increasing the mass but divinding the watts each coil will get based on thiers resistances.

You have no choice with a fixed voltage to lower the resistance to get more watts going through the circuit, but when you can adjust the voltage, it does'nt make any sense anymore.

No resistance = no heat.
No friction = no heat.
No restriction = no heat generated, as it is the work that need to be done to accomplish something that generate heat.

Provided that you have enough voltage to overcome the resistance, you can get more heat with less watts going through a circuit by increasing the resistance.

You can't change how things work in nature just by believing it work differently.

#38 (permalink)      3/29/2015 9:29:33 PM US Central   quote/reply + tips
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Snorkelwhacker
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Where did I say increasing resistance increases mass? I suggested low resistance with large gauge, high mass coils is a waste of power.

No watts = no heat.

Nothing has zero resistance.

I know, though, watts are meaningless. It's all about resistance. ::rolls eyes::
Rube Goldberg would get a kick out of "temperature control" devices.
#39 (permalink)      3/29/2015 9:57:01 PM US Central   quote/reply + tips
JPBel
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Snorkelwhacker wrote:

Where did I say increasing resistance increases mass? I suggested low resistance with large gauge, high mass coils is a waste of power.

No watts = no heat.

Nothing has zero resistance.

I know, though, watts are meaningless. It's all about resistance. ::rolls eyes::


Easy experiment to make.
Get the maximum temperature a 0.5ohm coil will reach at 5 watts vs a 2 ohms coil at 5 watts, then dare to get back to me saying resistance mean nothing.


Edited on 3/29/2015 at 10:12 PM. Reason:
#40 (permalink)      3/29/2015 10:30:42 PM US Central   quote/reply + tips
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Snorkelwhacker
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5 watts is 5 watts. The more important factor in which coil reaches a higher temp is the mass, assuming identical alloy.

I never said resistance means nothing, numbnuts. I merely laughed at your supremely stupid comment that watts mean nothing and that you're more concerned with heat.

That's like saying inches mean nothing, and that you're more concerned with centimeters.

In other words: it's fucking stupid.
Rube Goldberg would get a kick out of "temperature control" devices.
#41 (permalink)      3/29/2015 11:41:49 PM US Central   quote/reply + tips
JPBel
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Snorkelwhacker wrote:

5 watts is 5 watts. The more important factor in which coil reaches a higher temp is the mass, assuming identical alloy.

Wrong, it as nothing to do with mass.
More mass will only take more time to reach its maximal temperature.

It is not because you are passing 100W in a circuit that 100W will get dissipated as heat, and that has nothing to do with masses.

At any instant of time, the power P (watts) consumed by a resistor of resistance R (ohms) is calculated as: P =I^2*R = I*V =V^2/R where V (volts) is the voltage across the resistor and I (amps) is the current flowing through it.


The lower the resistance, the lower the voltage across it will be.
Voltage drop ring a bell ?

Vaping wise, wattage mean nothing without a resistance to create the heat.
Keep same wattage, increase the resistance, and more heat will be dissipated by that resistance.

JPBel wrote:
I prefer resistance, because no resistance = no heat.
But don't tell this to them, they are not ready for it.
They want watts, not heat.

Snorkelwhacker wrote:
30W = 102.4 BTU/hr

Who'da thunk?


Take your comment and put it back where it came from.

I never said resistance means nothing, numbnuts. I merely laughed at your supremely stupid comment that watts mean nothing and that you're more concerned with heat.


Never said that watts mean nothing, you are the one that interperted it that way.

Don't let your mind stay in the caveman age of mech mods, we have the regulated mods option now.
Welcome to the future.


Edited on 3/29/2015 at 11:48 PM. Reason: