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Difference between Mini protank 2 and 3?
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#1 (permalink)      3/15/2014 9:07:36 PM US Central   quote/reply + tips
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Ronniexx4
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Difference between Mini protank 2 and 3?
I have an authentic mini protank 2, the only difference I see is the stock drip tip and the base is a different colour. What's the difference?
Canada represent :)
#2 (permalink)      3/15/2014 10:02:16 PM US Central   quote/reply + tips
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skyrockets1uk
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The difference is dual coils what means your pro tank 2 coils is no use and builds are a lot harder in pro tank 3. That is why I change over to RBAs saves you $$$ and is a far better vape.

Edited on 3/16/2014 at 2:50 PM. Reason:
Godspeed on the Devil's Thunder. Fasttech don't pay me for this I just get a bonus.
#3 (permalink)      3/16/2014 7:33:11 AM US Central   quote/reply + tips
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TEFL0N_D0N_81
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skyrockets1uk is wrong. You can build single coils as well on the deck of the aerotank and the mini protank 3. As for RBAs, they are a better vape, but I still use the mini protank 2 for work. Much better carry and form factor.
Trying is the first step to failure... - Homer Simpson
#4 (permalink)      3/16/2014 9:25:18 AM US Central   quote/reply + tips
TXiOS420AppleAdvisor
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Agreed Teflon
#5 (permalink)      3/16/2014 3:16:01 PM US Central   quote/reply + tips
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skyrockets1uk
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So the answer in nothing keep your protank 2. Buy Aerotank base ($5) and build single coils on it.
Godspeed on the Devil's Thunder. Fasttech don't pay me for this I just get a bonus.
#6 (permalink)      3/16/2014 9:27:00 PM US Central   quote/reply + tips
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Ronniexx4
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I'll just assume that I should stick to my mini protank 2. I just ordered the Aerotank. Been wanting one of those suckers for a while now. Thanks guys.
Canada represent :)
#7 (permalink)      4/14/2014 2:56:23 AM US Central   quote/reply + tips
oisteink
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The difference is the number of coils. 2 coils in this compared to 1 coil in version 1 and 2.

You can say it's the 2nd generation of bottom-coils from Kanger.
Just like your mini protank 1 and 2 use the same coils as protank 1 and 2, this one share coils with protank 3 (and others).

- 2 coils will give you more string connecting with fluid, so more vapour.
- The thicker the thread, the more contact it gets so low ohms give more vapour (but also takes more electricity to heat up).
- As there are two paralell coils for your electricity to flow through, a 1.5 ohm dual-coil are two 3 ohm coils. This means to calculate how long your battery should last you, you need to account for two coils at 3 ohm.

Warning : theory ahead :

Example using 1.5 ohm dual-coil on an iTaste vv, set to give you 7.5 W (Because this is what I normally use :-)
3 ohm @ 7.5 W = 4.74 V pulling 1.58 A
As we have two of these we need to doubble the Amp so for two coils we pull 3.16 A
Our battery has 800 mAh (0.8 Ah). We will divide this by the number of Amps we use, and multiply it by 3600 (60*60) to get the answer in seconds rather than hours.
(0.8 / 3.16) * 60 * 60 = 911.4 seconds of usage. if you do 5 second pulls this is 182 pulls.

I've ordered two sets of these, one saying 1.5 ohm, one saying 2 ohm. For 2 ohm version the same would be:
4 ohm @ 7.5 W = 5.48V pulling 1.37 A
0.8 / 2.74 * 3600 = 1051 seconds or 210 pulls at 5 sec each.

So according to these theories I should get less vapour but more pulls off the 2 ohm compared to the 1.5 ohm.
#8 (permalink)      7/23/2014 4:54:59 PM US Central   quote/reply + tips
Mee.Yuki
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Dear Oisteink,

The final result is correct (consumption and time)
But the theory you presented is a little bit confusing and doesn't make sense.
I still don't know how you got those numbers and get the right final consumption result.

The theory is the following:

When you have a two-coils you never sum up the values because we are talking about "parallel resistances association".
Req = (R1*R2)/(R1+R2) = (1.5*1.5)/(1.5+1.5) = 0.75 Ohms
The equivalent resistance is 0.75 Ohms (for dual-coil 1.5 Ohms) and not 3 Ohms as you said.

According to your description that you are using iTaste VV (Voltage Variable) you set the Wattage to 7.5W.
So the resulting voltage is P=V(power 2)/R, so V=Square Root of (P*R) = SqRoot of (7.5*0.75) = 2.37 Volts (not 4.74V)
The consumption is I=P/V = 7.5/2.37 = 3.16A (now things start matching)
0.8Ah/3.16A = 0.2531 hours = 15.18 minutes = 911.4 seconds (Final results is the same, I just don't know how to get that :) )

The equivalent resistance for 2 Ohms dual-coil is:
Req = (R1*R2)/(R1+R2) = 1 Ohm and not 4 Ohms...
Following the same theory as above:
Voltage at battery is SqRoot of (7.5*1) = 2.73V (not 5.48V)
Consumption is 7.5/2.73 = 2.75A
0.8Ah/2.75A = 0.2909 hours = 17.45 minutes = 1047.27 seconds

And a very important thing at the end (in your conclusion): You'll get the SAME VAPOUR for both resistances (1.5Ohms or 2Ohms)
You will say: What?????? (LOL)

Yes, you will get the same vapour for both dual-coils because your power (of 7.5W) is the same at the end, since "Innokin iTaste VV" allows you to lock the power to a determined amount (in this case 7.5W).
What changes is ONLY the consumption... with 2 Ohms dual-coil you'll have 1047 (or 1051 seconds) agains 911 seconds.

Simple like that....
#9 (permalink)      10/5/2015 3:00:38 PM US Central   quote/reply + tips
EpicBunty
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Such theory much confusion very scared.

I suck at math bigtime will I have to do all these calculations or can I just measure my ohms, plug em in and start vaping!?